소개글
전자기학 7판,솔루션
목차
CHAPTER 1
CHAPTER 2
CHAPTER 4
CHAPTER 5
CHAPTER 7
CHAPTER 8
CHAPTER 9
CHAPTER 10
CHAPTER 12
CHAPTER 13
본문내용
CHAPTER 1
1.1. Given the vectors M = −10ax + 4ay − 8az and N = 8ax + 7ay − 2az, find:
a) a unit vector in the direction of −M+ 2N.
−M+ 2N = 10ax − 4ay + 8az + 16ax + 14ay − 4az = (26, 10, 4)
Thus
a =
(26, 10, 4)
|(26, 10, 4)| = (0.92, 0.36, 0.14)
b) the magnitude of 5ax +N− 3M:
(5, 0, 0) + (8, 7,−2) − (−30, 12,−24) = (43,−5, 22), and |(43,−5, 22)| = 48.6.
c) |M||2N|(M+N):
|(−10, 4,−8)||(16, 14,−4)|(−2, 11,−10) = (13.4)(21.6)(−2, 11,−10)
= (−580.5, 3193,−2902)
1.2. The three vertices of a triangle are located at A(−1, 2, 5), B(−4,−2,−3), and C(1, 3,−2).
a) Find the length of the perimeter of the triangle: Begin with AB = (−3,−4,−8), BC = (5, 5, 1),
and CA = (−2,−1, 7). Then the perimeter will be = |AB| + |BC| + |CA| =
√
√ 9 + 16 + 64 +
25 + 25 + 1 +
√
4 + 1 + 49 = 23.9.
b) Find a unit vector that is directed from the midpoint of the side AB to the midpoint of side
BC: The vector from the origin to the midpoint of AB is MAB = 1
2 (A+B) = 1
2 (−5ax+2az).
이하생략
참고 자료
없음
압축파일 내 파일목록
chapter01_7th_solution-vectorist.pdf
chapter02_7th_solution-vectorist.pdf
chapter04_7th_solution-vectorist.pdf
chapter05_7th_solution-vectorist.pdf
chapter07_7th_solution-vectorist.pdf
chapter08_7th_solution-vectorist.pdf
chapter09_7th_solution-vectorist.pdf
chapter10_7th_solution-vectorist.pdf
chapter12_7th_solution-vectorist.pdf
chapter13_7th_solution-vectorist.pdf